1=(x^2-4)/(x^2-x-6)

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Solution for 1=(x^2-4)/(x^2-x-6) equation: 


D( x )

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

x in (-oo:-2) U (-2:3) U (3:+oo)

1 = (x^2-4)/(x^2-x-6) // - (x^2-4)/(x^2-x-6)

1-((x^2-4)/(x^2-x-6)) = 0

(-1*(x^2-4))/(x^2-x-6)+1 = 0

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

(x+2)*(x-3) = 0

(-1*(x^2-4))/((x+2)*(x-3))+1 = 0

(-1*(x^2-4))/((x+2)*(x-3))+(1*(x+2)*(x-3))/((x+2)*(x-3)) = 0

1*(x+2)*(x-3)-1*(x^2-4) = 0

-x-2 = 0

(-x-2)/((x+2)*(x-3)) = 0

(-x-2)/((x+2)*(x-3)) = 0 // * (x+2)*(x-3)

-x-2 = 0

-x-2 = 0 // + 2

-x = 2 // * -1

x = -2

x in { -2} 

x belongs to the empty set

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